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What is the equation of the graph below? a. y = –1(x – 4)2 + 1 b. y = –1(x + 1)2 + 4 c. y = 1(x + 1)2 – 4 d. y = 1(x + 4)2 – 1
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I thinkits b, am i right?
vertex is \[(-1,-4)\]
you can see it right? the vertex i mean
oh so its c?
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yes, it is c!
b/c u have to flip -1 to 1 an then -4 stays
because of the following \[(x+1)^2\geq 0\] for any x, because it is a square. therefore the very least it can be is 0 and it is zero if x = -1 if x = - 1 then \[(x+1)^2=(-1+1)^20\] and \[(x+1)^2-4=(-1+1)^2=0-4=-4\]
so what would it be?
so i am right its c?
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than u
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