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Mathematics 13 Online
OpenStudy (anonymous):

What is the equation of the graph below? a. y = –1(x – 4)2 + 1 b. y = –1(x + 1)2 + 4 c. y = 1(x + 1)2 – 4 d. y = 1(x + 4)2 – 1

OpenStudy (anonymous):

OpenStudy (anonymous):

I thinkits b, am i right?

OpenStudy (anonymous):

vertex is \[(-1,-4)\]

OpenStudy (anonymous):

you can see it right? the vertex i mean

OpenStudy (anonymous):

oh so its c?

OpenStudy (anonymous):

yes, it is c!

OpenStudy (anonymous):

b/c u have to flip -1 to 1 an then -4 stays

OpenStudy (anonymous):

because of the following \[(x+1)^2\geq 0\] for any x, because it is a square. therefore the very least it can be is 0 and it is zero if x = -1 if x = - 1 then \[(x+1)^2=(-1+1)^20\] and \[(x+1)^2-4=(-1+1)^2=0-4=-4\]

OpenStudy (anonymous):

so what would it be?

OpenStudy (anonymous):

so i am right its c?

OpenStudy (anonymous):

than u

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