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COULD YOU SHOW YOU WORK? 1. x – 3 > –9 2. –2x + 1 ≤ –11 3. 10 < –3x + 1 4. 2(x + 5) > 8x – 8 5. –2(x – 3) ≥ 5 – (x + 3)
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1) x-3>-9 +3 +3 x>-6
1) add 3 to both sides
2) subtract 1 from both sides divide by -2 change the sense of the inequality
satellite73 which on are you doing?
\[-2x+1\leq -11\] \[-2x\leq -11-1\] \[-2x\leq -12\] \[x\geq -12\div -2\] \[x\geq 6\]
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that as #2
that was how u do it the work and all?
that was all the steps worked out. nothing omitted
oh ok
#3 takes two steps subtract 1 from both sides divide by -3 and change the sense of the inequality \[10 < –3x + 1\] \[10-1<-3x\] bet you can finish from there.
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