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What is the equation of the line of symmetry for the graph of y = 3(x – 2)2 + 1? a. x = –2 b. x = 1 c. x = 2 d. x = 3
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i think its a
3(x – 2)^2 + 1 a(x-h)^2+k line of symmtery is x=h so in your case h=2 so x=2
its 2 o r -2?
what did I write?
b/c dont u have to take ur sign with it? you for x = 2
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*wrote
yes, in general case a(x-h)^2 symmerty line -> x=h a(x+h)^2 =a(x- -h)^2 --> x=-h
so its a?
is it?
no, it is x=2
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buy why if before it has a -
IF IT WERE 3(x + 2)^2 + 1 then it would be x=-2
oh so its the opposite sign?
yes
oh i get it thank u!
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