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Given the sequence 6, 18, 54, 162, ..., which expression would give the fifteenth term?.
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first term is 6, second term is 3x6, third it 3^2x6, so 14th is 3^13x6
\[6*3^{14}=28697814 \]
oh sorry 15th term is just 3^(14)x6
\[T_n=6 \times 3^{n-1} \]
foolfor the nth term gets a medal
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Tn=ar^n-1
n=position of the term r=common ratio a=value of the first term
It is a geometric progression
Answer is 28697814
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