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(2x^-5y^4)^3
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(2x^-5y^4)^3 somethings missing after 2x^, or was it supposed to be this way? (2x^(-5y^4))^3
its to the negative 5 i think
yeah -5 is the exponent
you would cube the 2, and an (x^n)^m you multiply powers so x^-5^3 = x^-15 the answer is 8x^-15y^12
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