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how do you solve: 2x+1= negative square root of 12
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since you raised both sides to an even power, you should check your results afterwards
wait
why did you square both sides/
I don't know...:/
lol
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subtract 1 on both sides first
and then divide by 2 lol @ turing
\[2x+1 =- \sqrt{12} => 2x=-1- \sqrt{12}=>x=\frac{-1-\sqrt{12}}{2}\]
and there is a perfect square in 12 12=3(4)=3(2^2) so you can simplify more
subtract 1, divide by 2
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yep lol
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