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Mathematics 14 Online
OpenStudy (anonymous):

You have 8 objects of similar size, but one object weighs a little bit more than the others. Given a balance scale, you must find out which object it is, but you may only use the scale twice. What do you do?

OpenStudy (2bornot2b):

If you allow me thrice, then I have the answer

OpenStudy (anonymous):

Great; they say it can actually be done with only 2 "weighing" steps but still, I wanna see your answer!

OpenStudy (2bornot2b):

Just divide the 8 things into two groups, and place it in each of the pans of your balance.

OpenStudy (2bornot2b):

*of course two equal groups of 4

OpenStudy (2bornot2b):

So now you know when 4 contains the heavier one

OpenStudy (2bornot2b):

Divide that group into 2 groups each of 2,

OpenStudy (2bornot2b):

Now you know which two contains the heavier one

OpenStudy (anonymous):

how about 3 and 3 for the first weighing?

OpenStudy (2bornot2b):

Now again place them, and you know the culprit

OpenStudy (anonymous):

@satellite Great; what's the rest

OpenStudy (anonymous):

then if they are equal it is one of the other two, one weighing does it

OpenStudy (anonymous):

and if it is one of the groups of 3, then weight two out of the three: if they are equal then it is the third

OpenStudy (2bornot2b):

satellite73 solved it

OpenStudy (anonymous):

i think that does it

OpenStudy (anonymous):

Very cool!

OpenStudy (anonymous):

here is a question, that i can do but always have to start fresh because i always forget. how do i multiply two 2 digit numbers with only 3 multiplications? example 24 x 53

OpenStudy (anonymous):

i am guessing adg knows because it is related to computer algorithms.

OpenStudy (2bornot2b):

Now solve this: There are 10 cigarette packets, each containing 10 cigarettes. One of the packets contain cigarettes which are a bit heavier than the cigarettes in any of the other packets. Although each cigarette in anyone packet weighs the same. Now with just one weighing you need to find out the culprit box.

OpenStudy (anonymous):

i have seen this one before so i keep quiet

OpenStudy (2bornot2b):

great satellite73!

OpenStudy (anonymous):

just select cigarettes from each box and compare!

OpenStudy (2bornot2b):

You are allowed to weight only once

OpenStudy (2bornot2b):

However, I must mention, you are allowed to use standardized weights

OpenStudy (anonymous):

right empty one box, leaving 1 cigarette in, and stuff that box with cigarettes from other boxes. and then..... I'm stuck :(

OpenStudy (2bornot2b):

Oh! Just don't try it that way. Keep it with you for a few days, then come back. You will surely have solved it by then

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

alright... just look at the boxes and compare the weights...

OpenStudy (anonymous):

ok i remember now. you can multiply 53 times 24 with 3 multiplications instead of 4

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