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By writing x as 4+(x-4) and using the Maclaurin expansion for ln(1+t), or otherwise, find the first four non zero terms in the Taylor series expansion for ln(5x) about x = 4.
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ln(5x) = ln 5 + ln x = ln 5 + ln(4 + (x-4)) = ln 5 + ln 4 + ln(1 + (x-4)/4) = ln(20) + ln(1 + u), where u = (x-4)/4 Now use the series expansion for ln(1+u)
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