Question

Find a quadratic equation with the roots 3 + 4i and 3 - 4i. HELP PLEASE!

Answer 1

when given roots; just reconstruct the poly with them

Answer 2

x=(a,b)

(x-a)(x-b)=0

Answer 3

if we are given roots as a and b , then the equation is given as
(x-a)(x-b)=0
here the roots are 3+4i and 3 -4i
(x-(3+4i))(x-(3-4i))
x^2-(3+4i+3-4i)x-(9-16)=0
x^2-6x-7=0

Answer 4

if anything:\[x=\frac{-b+\sqrt{b^2-4ac}}{2a}\]

Answer 5

3 = -b/2a

-3/2 = b/a

2x^2 -3x + c = 0 is a sort of way to see it

Answer 6

except for I mistyped it lol

Answer 7

-6/1 = b/a

x^2 -6x + c = 0

Answer 8

but my answers say x^2 + 6x + 25 :s

Answer 9

The simplest "Vieta's Formula" is x^2 - (sum)x + (product)

in this case we get x^2 - 6x + 25