An object is thrown vertically upward at 18 m/s from a window and hits the ground 1.6 s later. What is the height of the window above the ground? (Air resistance is negligible.) a. 3.7 m d. 37 m b. 16 m e. 41 m c. 21 m

Question

jamesj · Answer

You want to write down an equation for the position of the object at time t, call it y(t).
y(t) = something involving initial velocity + something involving gravity.

Then evaluate y(t=1.6 seconds) to find where the ground is.

jamesj · Answer

Hint:  if there were no gravity, then
y(t) = 18t

Now, what does gravity do to that equation?

anonymous · Answer

y(t)=18t-5t^2 
plugin value for time t=1.6s 
y=16m

anonymous · Answer

ohhhhh!! is y(t) = Vi + g the equation?

anonymous · Answer

Why is y(t) = 18t - 5t^2? What is the general equation?

anonymous · Answer

heelp! D:

anonymous · Answer

http://ibphysicsstuff.wikidot.com/uniformaccmotion it is equation8 that u are looking fo ALL THESE ARE FOR UNIFORMLY ACCELERATED MOTION