Give an equestion for the line that contains ( 3,2 ) and (5,-2 )
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OpenStudy (mertsj):
Slope = (-2-2)/(3-5)=-4/-2=2
So now we know the slope is 2 plug one of the points and the slope into point-slope form.
OpenStudy (mertsj):
Can you do that?
OpenStudy (anonymous):
I Dont Get It
OpenStudy (anonymous):
find slope
m = y2 - y1 / x2 - x1
m = -2 - 2 / 5 - 3
m =-4 / 2
m = -2
find b
y = mx + b
pick any coordinate
2 = -2 (3) + b
2 = -6 + b
8 = b
your equation is
y = -2x + 8
OpenStudy (mertsj):
Here is point-slope form:
y-y1=m(x-x1)
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OpenStudy (mertsj):
Ok. Dada will help you, I see.
OpenStudy (anonymous):
lol i showed all the steps so you can learn from it
I believe Mertsj is right
you should learn how to do it yourself
OpenStudy (anonymous):
How would you grap that
OpenStudy (amistre64):
most basic graphing is to fill in some xs to find the ys to plot
OpenStudy (amistre64):
the equation is a rule for the graph; all it has to be be is followed
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OpenStudy (amistre64):
another simpler way is to plot the 2 points given and draw a line between them
OpenStudy (anonymous):
but how would you do that
OpenStudy (amistre64):
the equation itself just defines the line;
OpenStudy (amistre64):
they gave you 2 points right? you know how to plot a point?