Give an equestion for the line that contains ( 3,2 ) and (5,-2 )
Slope = (-2-2)/(3-5)=-4/-2=2 So now we know the slope is 2 plug one of the points and the slope into point-slope form.
Can you do that?
I Dont Get It
find slope m = y2 - y1 / x2 - x1 m = -2 - 2 / 5 - 3 m =-4 / 2 m = -2 find b y = mx + b pick any coordinate 2 = -2 (3) + b 2 = -6 + b 8 = b your equation is y = -2x + 8
Here is point-slope form: y-y1=m(x-x1)
Ok. Dada will help you, I see.
lol i showed all the steps so you can learn from it I believe Mertsj is right you should learn how to do it yourself
How would you grap that
most basic graphing is to fill in some xs to find the ys to plot
the equation is a rule for the graph; all it has to be be is followed
another simpler way is to plot the 2 points given and draw a line between them
but how would you do that
the equation itself just defines the line;
they gave you 2 points right? you know how to plot a point?
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