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If you throw a dice 6 times, what's the chance that you'd get a six on: a: exactly one of the throws. b: one or more of the throws
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(1/2)^6
a) (5/6)^5*1/6 you need to land on everything EXCEPT 6 5 times out of 6 so 5/6^5 and you need one 1/6 so you multiply it together b)(1/6)^6 This, you want to only get one all 6 times so 1/6^6 It's just (1/#of possiblities)^(number of "rolls" or trials)
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