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jimthompson5910 (jim_thompson5910):
(4x^2-25)/(2x-5)
((2x-5)(2x+5))/(2x-5)
2x+5
OpenStudy (anonymous):
im still confused . can you explain how you got this?like in words?
jimthompson5910 (jim_thompson5910):
I factored 4x^2-25 to get (2x-5)(2x+5) using the difference of squares rule
jimthompson5910 (jim_thompson5910):
then i divided and canceled out the "2x-5" terms
jimthompson5910 (jim_thompson5910):
to be left with 2x+5 as the answer
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OpenStudy (anonymous):
ok but the answers show more. can i show you my choices?
jimthompson5910 (jim_thompson5910):
sure thing
OpenStudy (anonymous):
2x – 5, with the restriction x ≠ – 5/2
2x + 5, with the restriction x ≠ 5/2
2x – 5, with the restriction x ≠ 5/2
2x + 5, with the restriction x ≠ – 5/2
jimthompson5910 (jim_thompson5910):
well you can't divide by zero, so 2x-5 cannot be zero
if it were, then
2x-5=0
2x = 5
x = 5/2
which means that x = 5/2 makes the denominator zero.
So to avoid dividing by zero, we just add the restriction that x cannot be 5/2
So the answer is choice B
OpenStudy (anonymous):
thank you
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