Question

limit as x approaches 0 of (sin 5x)/7x?

Answer 1

what's the limit as u --> 0 of (sin u)/u

Answer 2

1

Answer 3

right. So think about trying to rewrite your equation in that form. Hint: the final answer is not 1.

Answer 4

I am hopeful that I can multiply the numerator by 5x/5x. Then I can cancel out the leftover x in the numerator with the x in the denominator (5x/7x, where the x's cancel
) and have 5/7?

Answer 5

yes

Answer 6

Thanks...this is very humbling...haven't done algebra in years and I'm about a week into a calculus course. You've been very helpful twice now.

Answer 7

I don't even remember the first time, but I'm glad I have been.

Keep at it. It's fun and intellectually very satisfying.

Answer 8

I asked about delta-epsilon proofs earlier in the day. I am studying very hard. Thanks again.