limit as x approaches 0 of (sin 5x)/7x?

Question

jamesj · Answer

what's the limit as u --> 0 of (sin u)/u

anonymous · Answer

1

jamesj · Answer

right.  So think about trying to rewrite your equation in that form.  Hint: the final answer is not 1.

anonymous · Answer

I am hopeful that I can multiply the numerator by 5x/5x.  Then I can cancel out the leftover x in the numerator with the x in the denominator (5x/7x, where the x's cancel
) and have 5/7?

jamesj · Answer

yes

anonymous · Answer

Thanks...this is very humbling...haven't done algebra in years and I'm about a week into a calculus course.  You've been very helpful twice now.

jamesj · Answer

I don't even remember the first time, but I'm glad I have been.

Keep at it.  It's fun and intellectually very satisfying.

anonymous · Answer

I asked about delta-epsilon proofs earlier in the day.  I am studying very hard.  Thanks again.