Question

Can someone verify I've done this right? Lim x->0 of (sin^2 (5x))/7x^2. I've come up with 25/49.

Answer 1

\[\lim_{x \rightarrow 0}\frac{\sin(5x) \cdot \sin(5x)}{7 \cdot x \cdot x}=\frac{25}{7}\lim_{x \rightarrow 0}\frac{\sin(5x)}{5x} \cdot \frac{\sin(5x)}{5x} \]

Answer 2

the 49 is a mistake

Answer 3

yes it is just 7 on bottom

Answer 4

what the talented myininaya said

Answer 5

Devilry! I accidently multiplied 7x twice.
I shouldn't be trusted with algebra. Thanks.

Answer 6

no one should be trusted with algebra

Answer 7

its all to get us all

Answer 8

i'm jk
mistakes happen lol