Question

cg^3+27c
Factor Help Please

Answer 1

what can you GCF out of both terms?

Answer 2

c

Answer 3

right so now you have c(g^3+27). now you need to set it up ( )( ). what are you going to put in the front of the parenthesis?

Answer 4

by front i mean the first spot in the template c(____ _____)(_____ _____)

Answer 5

i am really not sure how to figure that part out??

Answer 6

ok. so you want the variable in the first spot in each set of parenthesis (it's not a "law" but it keeps it cleaner). so, because you have an odd exponent that you cant split up evenly, one gets g^2 while the other gets g. make sense?

Answer 7

yes i got it

Answer 8

so now what does your template look like?

Answer 9

c(g^2______)(g_____)

Answer 10

right. now we need to split up 27 so that when you multiply the two numbers together, you get 27. so what are factors of 27

Answer 11

p and 3

Answer 12

9 sorry not p

Answer 13

also, the two numbers should add up to the middle term…in this case 0. so we need to find numbers that multiply to 27 but add to zero.

Answer 14

so is it 27 and 1 or 27 and 0

Answer 15

ok. i have a question. what math are you in because this is not the (___ ___) (___ ___) setup that we had. it's (___ ___) (___ ___ ___). this might take longer to explain

Answer 16

math 035

Answer 17

what grade is that?

Answer 18

i go to a community college the name of the class is fundamental of algebra 2

Answer 19

ok. sorry i wasnt trying to be creepy or anything. its just that we covered this in class today

Answer 20

no its fine

Answer 21

so now we are looking at the sum or difference of two cubes…which makes a lot more sense, as the cube root of both these terms is "pretty"

Answer 22

so the GCF is still c, but now we are looking at the setup of
a^3+b^3=(a+b)(a^2-ab+b^2) otherwise known as the S.O.P. method. the first sign in the parenthesis stays the Same as the original problem the second sign is Opposite as the original, and the third is ALWAYS Positive.

Answer 23

if a and b represent the original terms in the equation, what fills in the parenthesis?

Answer 24

ok. you left but ill finish the problem in case you come back later so you can see how its done.

Answer 25

the first part is just the original problem because your a=g and your b=3

a=g and b=3
so your second part is (g+3)

a^2 is g^2 and ab is 3g and b^2 is 9
so your third part is (g^2-3g+9)

put it all together and your final answer is
(g+3)(g^2-3g+9)

Answer 26

hope this helped

Answer 27

thank you so much. my internet mess up on me. I felt so rude cause i know u were really trying to help me. Thanks so much :)