Question

Please help me!! Ahh calculus

Answer 1

\[\lim_{x \rightarrow 0} \left[ x ^{2}\sin (1/x) \right]\]

Answer 2

No limit. You can't divide by 0.

Answer 3

i tried that. it doesn't work like that my teacher said I was wrong

Answer 4

Does not exist.

Answer 5

Answer is 0
Use the squeeze theroem

Answer 6

what is the squeeze theroem

Answer 7

It says that if you have three functions, and the middle function lies in-between the upper and lower one, the limit of the middle function is above the lower and below the upper function. I didn't really understand it, seemed like common sense. Maybe someone can explain more fully to you.