Question

Find the equation of the line that is parallel to the line 2x-3y=-4 containing the point (-5,3)

Answer 1

first you want to get it in slope intercept form

Answer 2

ok

Answer 3

slope intercept form= y=mx+b

Answer 4

lets put this in slope intercept form!
2x-3y=-4
subtract 2x on both sides
-3y=-2x-4
divide by negative 3 on both sides
y-2/3x+4/3

Answer 5

mak that be y=2/3x+4/3

Answer 6

Ok, so we will start from solving that given line

First of all, solve that line in the form of y=mx+c
Where "m" is the slope.

Note: Parallel line means same slope.

2x-3y=-4

Solve for y
\[3y = 2x +4\]\[y = \frac23x + \frac43\]
Comparing this with y=mx+c
Slope is "m", so slope we get is 2/3.


Now insert the point given and the slope in the formula, (i.e. slope and (-5,2)
\[y-y_1 = m(x-x_1)\]
\[y - 2 = \frac23 (x-(-5))\]
Im sure u can solve now! :)

Answer 7

so now lets use a formula called point slope form. do you know the formula for that?

Answer 8

how do you get y-2?

Answer 9

It's given in the question, Point (-5,2)

Answer 10

its (-5,3)

Answer 11

Oh sorry. i overread. make it 3 please.

Answer 12

\[y−2=2/3(x−(−5))\]

y=2/3x +5.33

Answer 13

i prefer writing that in fractions

Answer 14

is that the correct answer?

Answer 15

Nope.

Answer 16

whats the answer?

Answer 17

\[y = \frac23 x+\frac{19}{3}\]

Answer 18

its not 19/3. (2/3)*5+2= 5.33

Answer 19

hold on..

Answer 20

ok?

Answer 21

lol, u made a mistake,
(2/3)5 + 3

Answer 22

hahah wow. Thanks for catching that!

Answer 23

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