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\[\lim_{x \rightarrow 4}((1/(x-3))-(1-1))/(x-4) \] and the answer is not 0
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is there a typo in this question..?
nope
in the 2nd part there seems to be a missing bracket... (1 -1))/(x - 4)
oh there is a typo it should be ((1/(x-3))-(1/1))/(x-4)
still an odd number of brackets... but I think you need the limit property \[\lim_{x \rightarrow a} f(x)- g(x) = \lim_{x \rightarrow a} f(x) - \lim_{a \rightarrow a} g(x)\]
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