Question

Solve: 2r^2-11x+5=0
Thanks :)
p.s. explain?

Answer 1

Do you know the quadratic formula?

Answer 2

The variables should be the same, right?

Answer 3

Agreed.

Answer 4

Good eye.

Answer 5

Good eye? It was blatantly obvious, lol :P

Answer 6

oh right! My teacher made a typo, lol. they should both be r's. and no, I don't remember anything from algebra 1! Which is bad :/

Answer 7

How do you know they shouldn't both be x's?

Answer 8

well, letters don't really matter. whichever you replace, they would still be the same problem.
just different letters.

Answer 9

I think he's being humorous, sakigirl.

Answer 10

can someone just help me? lol. i'm kinda stuck on this question >_<

Answer 11

2r^2-11r+5=0
2r^2-10r-1r+5 = 0
2r(r-5)-1(r-5) = 0
(r-5)(2r-1) = 0

r = 1/2
r = 5

Answer 12

Hero is right.

Answer 13

You can also use the quadratic formula, which is faster i guess.
\[\large x=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \]

Answer 14

Nope, I'm faster. The quad formula is whack.

Answer 15

Hahaha!

Answer 16

Mimi uses it because she can't factor :P

Answer 17

Nope, well..the using the quadratic you won't need to think much as to factor where you mgiht make stupid mistakes.

Answer 18

Mimi, you forgot to put the line that protects your discriminant :P

Answer 19

what line?

Answer 20

The square root line.....(DUH) :P

Answer 21

wtf..there's nothing wrong :/
You're confusing me :/

Answer 22

lol, just teasing. Don't cry on me :P

Answer 23

HERO. one last question. i beg.

Answer 24

Oh..gawd, confusing a poor kid that just woke up :'(

Answer 25

Here we go again with the "poor little kid" retreat line you always pull :P

Answer 26

You dont have the right to alternate my phrases i said "poor kid" NOT "poor little kid" :P

Answer 27

poor kid = poor little kid

To me it's the exact same thing. A sympathy plea

Answer 28

kwell, I'm just gonna ask. 2c^2+c-10=0

Answer 29

Mimi can use her quad form to help you

Answer 30

Excuse me, its not a "sympathy plea" i never told you to be pity me. GOsh people these days who dont have common sense.

Answer 31

i don't remember crap about the quad form hah.

Answer 32

Because Hero is unable to factor it :P

Answer 33

\[\large c=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \]
\[\large c=\frac{-(1)\pm\sqrt{(1)^{2}-4(2)(-10)}}{2(2)} \]

Answer 34

2c^2+c-10=0
2c^2+5c-4c-10 = 0
c(2c+5)-2(2c+5) = 0
(2c+5)(c-2) = 0

c = -5/2, 2

Answer 35

Mimi jinxed me.

Answer 36

lol, i told you that you will make stupid mistakes :P
The factor method is such a FAIL!

Answer 37

Mimi made careless mistakes! :O

Answer 38

Quad Form is an even bigger fail, especially when you depend on it so much Mimi :P

Answer 39

I know about 5 different factor methods

Answer 40

None of which include the dreaded quad form

Answer 41

how would you use the quad form on questions like 25m^2-64=0??

Answer 42

What? You dont have the right to say that its a fail since i got it right in the first go, not like you who go it WRONG! EVen during exams it would be a waste of time to do it again :P

Answer 43

a.k.a binomials.

Answer 44

25m^2 - 64 = 0
25m^2 = 64
m^2 = 64/25
m = sqrt{64/25}
m = plus or minus 8/5

Answer 45

Btw, quadratic formula can only be used for ax^3+bx+c

Answer 46

Oh right, I totally knew that.

Answer 47

ax^2*

Answer 48

Yeah, the quad form is LIMITED

Answer 49

While I was working hard to provide your solution sakigirl. Mimi, started making useless comments

Answer 50

hahah, forgetting the line of the square root. Oh silly her.

Answer 51

I was trying to help her know a better method to solve it which is quicker. I was being nice

Answer 52

I was being nicer :P

Answer 53

whaat? forgettng the line of the square root?

Answer 54

lol

Answer 55

Yeah! and Hero commented on it

Answer 56

lol

Answer 57

lol, sorry to say i think you should scroll up, i never make those carelless mistakes.

Answer 58

you just made one, then auto corrected it. Putting ax^3 , then ax^2. Such silly mistakes :P

Answer 59

its called a TYPO, you make stupid mistakes as well argh..i should never comment in questions that you are in anymore.