Question

Find a number k such that the given equation has exactly one real solution.
x^2-kx+4=0

Answer 1

the answer is 4 or -4

Answer 2

you just use the discriminant

Answer 3

use b^2 - 4ac = 0 from the GQF..... or (-k)^2 - 4x1x4 = 0 and solve

Answer 4

ax^2+bx+c=0
for one real solution
D=b^2-4ac=0
here a=1
b=-k
c=4
K^2-4*1*4=0
k^2-16=0
so \(k=\pm 4\)