these are really hard for me.. Can someone help? The vertex of y = 9 - 8x - x2 is (-4, 25) True or False What is the vertex for the function? y = x2 - 4x - 3 Anwsers: (-1, 2) (0, -3) (1, -6) (2, -7)
I am assuming that when you say x2 you mean \[x^2\]
yes
(2,-7)
Can you help me with the previous ones i posted?
To do this, we find the axis of symmetry, which (in standard form of ax^2 + bx + c) is x = -b/a which in this case is -8, then we plug that into x to get the y-value of the vertex, 9, so the vertex is (-8, 9)
so false
can you help me with these two? What are the values of a, b, and c in the function? List them in order with commas, such as 1,-2,3. y = -2x2 + 5x - 4 What is the vertex for the function? (You will want to find the axis of symmetry first.) Write as an ordered pair, leaving no spaces, such as (1,-4). y = -3x2 + 6x
look at the standard form i posted above.
i dnt get it
\[y = ax^2 + bx + c\]
??
now you can do the first one, then look how I found the axis of symmetry above, -b/a, in this case on the second question -6/-3 = 2
Ok, What about the first one?
\[y = ax^2 + bx + c \] this is the standard form of a quadratic equation, quadratic means that the highest exponent is 2 such as \[x^2\]
OK,
find the coefficients of x^2 and x in their respective places relative to a and b, c is the constant number on the end (-4)
i got it :)
One more? Thanks so much for your help! Which coefficient in the function tells us that the parabola for the function will point downward? y = -2x2 + 5x - 4
Anwsers: -2 5 -4
the direction of the parabola depends on whether the coefficient of the x^2 term is positive or negative. If it is positive such as 5x^2 it will point up, but -3x^2 would point down. In this case -2 is the coefficient which means it points downward
ohhh kk!!
HOW DO I FIGURE THIS OUT \[6\sqrt{2} - 3\sqrt{2}\]
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