Question

Write the equation of the line that is parallel to the line 4x − 3y = −12 and passes through the point (−3, 4).

Answer 1

y=-4/3x

Answer 2

first find slope of 4x-3y = -12
y = 4/3 x + 12
so slope is 4/3
and this is also the slope of the reqd line as they are parallel
use general form:
y-y1 = m(x-x1) where m = slope and a point on line is (x1,y1)
so
y-4 = (4/3) (x - (-3))
y - 4 = (4/3)x + 4
multiply through by 3
3y - 12 = 4x + 12
3y - 4x = 24 is the equation you want

Answer 3

you can check this out by plugging in x = -3 , y = 4:

3(4) - 4(-3) = 12 + 12 = 24

Answer 4

and if you rearrange the equation
3y = 4x + 24
y = (4/3) x + 8

- so the slope = 4/3