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f(x)=-15x+1 g(x)=-15x^2-20x-5 find (gof)(-3)
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woah that looks confuzing, okay: f(x)=15x+1 g(x)=-15x\[^{2}\]-20x-5 find (g o f)(3)
*-3, sorry
f(x)=-15x+1 g(x)=-15x^2-20x-5 f(-3) = -15(-3) + 1 = 45 + 1 = 46 (g o f)(-3) = g(f(-3)) = g(46) g(46) = -15(46)^2 - 20(46) - 5 = -31740 - 920 - 5 = -32665
That should be the correct answer
dude you're awesome. i remember that now. so you solve f(-3) and then put it into g ?
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The general formula is: (f o g)(x) = f(g(x)) But in this case we have: (g o f)(-x), so we write: (g o f)(-x) = g(f(-x)), then solve.
sweethanks !!! could you help me with one more problem?
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