Question

I don't even know where to begin at, let alone understand how to do this....
Test the following equation for symmetry. Show all work. x=y^2-6

Answer 1

f(-y) = f(y), its even; f(-y) = -f(y) its odd; if neither of those then its neither

Answer 2

first replace y with -y:
x = (-y)^2 - 6
this is the same as x = y^2 - 6
so the graph is symmetrical about the x - axis

Answer 3

if we try replacing x with -x the above is not found so not symmetrical about y-axis

Answer 4

easy pick a y-value, say y = 2, then use the neg, y=-2
now see if they give you the same x value

x = 2^2 -6 = -2
x = (-2)^2 -6 = -2