36.0kn/c=2(8.99x10^9)(Q/2.59)/.197
solve for Q

Question

36.0kn/c=2(8.99x10^9)(Q/2.59)/.197
 solve for Q

jamesj · Answer

The right hand side, RHS is 
$$ RHS = 2(8.99 \times 10^9)(Q/2.59)/.197 $$
$$ = (3.524 \times 10^{10})Q $$
$$ = \frac{36.0kn}{c} = LHS $$

Now it should be easier for you.

jamesj · Answer

Yes?

jamesj · Answer

chan ... talk to me

jamesj · Answer

ok ... hope that helped.  find me or someone in Physics chat if you need more help

anonymous · Answer

i just didn't know how to deal with the Q/2.59

jamesj · Answer

yes ... just put the 2.59 and the 0.197 in the denominator.

anonymous · Answer

so what did you get as a final answer.. just to compare and make sure i did it right

jamesj · Answer

I didn't calculate the final answer, but it's obviously
Q = (some constant, of order -9 or so)*(kn/c)

anonymous · Answer

thanks man.. some one that finally helped me and didn't start spittin out more complicated formulas

jamesj · Answer

sure.  Come back soon with some more Physics questions.