Question

36.0kn/c=2(8.99x10^9)(Q/2.59)/.197
solve for Q

Answer 1

The right hand side, RHS is
\[ RHS = 2(8.99 \times 10^9)(Q/2.59)/.197 \]
\[ = (3.524 \times 10^{10})Q \]
\[ = \frac{36.0kn}{c} = LHS \]

Now it should be easier for you.

Answer 2

Yes?

Answer 3

chan ... talk to me

Answer 4

ok ... hope that helped. find me or someone in Physics chat if you need more help

Answer 5

i just didn't know how to deal with the Q/2.59

Answer 6

yes ... just put the 2.59 and the 0.197 in the denominator.

Answer 7

so what did you get as a final answer.. just to compare and make sure i did it right

Answer 8

I didn't calculate the final answer, but it's obviously
Q = (some constant, of order -9 or so)*(kn/c)

Answer 9

thanks man.. some one that finally helped me and didn't start spittin out more complicated formulas

Answer 10

sure. Come back soon with some more Physics questions.