Question

Let g(x)=2x^2+2x+1. Find the value of c between 1 and 3 such that the average rate of change of g(x) from x=1 to x=3 is equal to the instantaneous rate of g(x) at x=c.

Answer 1

do just plug in 1 and 3 and do the rate of change and then plug in x and c and do the same?

Answer 2

so do this
\[g'(c)=\frac{g(3)-g(1)}{3-1}\]

Answer 3

ok i get 10 doing that

Answer 4

Have you plugged into the formula I gave you?

Answer 5

find g'
then find g'(c)
and set that equal to the slope of the secant line from x=3 to x=1

Answer 6

you're losing me lol

Answer 7

do you know hot to find g'?

Answer 8

4x + 2

Answer 9

and then plug in 1 and 3?

Answer 10

\[4c+2=\frac{g(3)-g(1)}{3-1}\]

Answer 11

ok so the answer is 2

Answer 12

thanks

Answer 13

\[4c+2=\frac{2(3)^2+2(3)+1-[2(1)^2+2(1)+1]}{2}\]

Answer 14

ok i have another similar prob that i need help with... ill post it on the main thing