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OpenStudy (smurfy14):
y=cos(-0.4x) has a horizontal stretch of..? PLEASE HELP
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OpenStudy (anonymous):
you mean period?
OpenStudy (smurfy14):
oh yes
OpenStudy (anonymous):
are you looking for the period of
\[\cos(-.4x)\]?
OpenStudy (smurfy14):
yes
OpenStudy (smurfy14):
im looking for something like "it stretches X..."
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OpenStudy (anonymous):
period of
\[\cos(x)\] is
\[2\pi\] so period of
\[\cos(bx)\] is
\[\frac{2\pi}{b}\]
OpenStudy (anonymous):
in your case you get
\[\frac{2\pi}{.4}=5\pi\]
OpenStudy (smurfy14):
no heres an example: y=-3cos1/2x has a horizontal stretch of 2
but i cant figure out what it would be for this problem
OpenStudy (anonymous):
so period goes from 2 pi to 5 pi
OpenStudy (anonymous):
oooooooooooooooh silly way to word the problem. in your case
\[\cos(\frac{1}{2}x)\] teh "stretch" was 2
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OpenStudy (anonymous):
in other words the reciprocal of coefficient. the reciprocal of .4 is 5, so stretch is 5
OpenStudy (smurfy14):
ohhhkay so you dont have to include the whole thing like 2/5=5/2 you just take the numerator?
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