Question

Find a vector U that is tangent to the graph of y=x^2-x+3 at the point (2,5)

Answer 1

slope is 5
vector is

Answer 2

The answer is actually <1, 3> and I am asking for an explanation why

Answer 3

oh...sry, that's right

Answer 4

Using derivatives, if you get the first derivative of the quadratic above, we get slope=2x-1
when we plug 2 in, we get slope=3
put this in vector form, we get (1,3)

Answer 5

added 1 by mistake on the first try :(

Answer 6

ah, that simple. Thanks!

Answer 7

welcome!