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Mathematics 21 Online
OpenStudy (anonymous):

Factor this expression. Check by multiplying factors. x^2y+axy+abx+a^2b

OpenStudy (anonymous):

factor demon to the rescue!

myininaya (myininaya):

We should try factoring by grouping First two terms have xy in common so we can write \[xy(x+a)+abx+a^2b\] Last two terms have ab in common so we can write \[xy(x+a)+ab(x+a)\]

OpenStudy (anonymous):

\[(x+a) (xy+ab)\]

myininaya (myininaya):

Yes that is the final answer :)

OpenStudy (anonymous):

"factor by groupies"

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