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sin(theta +alpha)sin(theta -alpha) =?
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use the sine double angle formulas it should be (sin(theta)cos(alpha)+sin(alpha)cos(theta))*(sin(theta)cos(alpha)-sin(alpha)cos(theta))
oh i see thank you! can you help me with another question tan(45degrees +a) +tan(45degrees -a)
same deal, use the tan angle sum identity [(tan(45 degrees)+tan(a))/(1-tan(45 degress)tan(a))]*[(tan(45 degrees)+tan(a))/(1-tan(45 degress)tan(a))] then replace tan(45 degrees) with 1 since tan(45 degrees) =1
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