please help on this math question !
Question number 6 confuses me
http://www.haeseandharris.co.nz/nz/samples/nz11_12.pdf can you also help me on question 2 page 214. the website has the textbook with the picture
point (3,a) means a = y coordinate at this point so you get a right angled triangle as in drawing:
sorry i meant page number 327
how would i solve for it?
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by pythagoras a^2 = 5^2 - 3^2 = 16 so a = 4
jimmrey after u are done with this question help me
second part of q 6: gradient of AP = 4 / (3--5) = 4/8 = 1/2 ..... BP = 4 / (3-5) = -2
i have a question also from the website
http://www.haeseandharris.co.nz/nz/samples/nz11_12.pdf page 327 question number 2a
and 2c
6 c : - ANGLE APB = right angle because gradient of BP * AP = -1
2a average speed = distance/time 920 / 11 = 83.6
oh alright how about question 3
3c part ii
and 2c
2c greatest average speed is where the graph is steepest can u identify this?
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