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Explain how to do this Lim 3x^2(x+1) /(over) (x +1) x->-1 = ?
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Hey matt. :D
\[\lim_{x \rightarrow -1}3x^2=3(-1)^2=3(1)=3\]
\[ \frac{x+1}{x+1}=1\]
Hey !
How would you calculate that limit using the Definition?
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let me rephrase that \[\frac{x+1}{x+1}=0 , x\neq -1\]and since we are taking a limit as x approaches -1 we know for certain \[x\neq -1\]
=0?
TYPO!!
let me rephrase what sallielte rephrased
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See Attachment ^ .
\[\frac{x+1}{x+1}=1 , x\neq -1 \]
any questions matt?
Kinda makes sense
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