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Mathematics 16 Online
OpenStudy (anonymous):

CUBEROOT(-16a^3b^8)

OpenStudy (anonymous):

\[\sqrt[3]{-16a^3b^8}\]

OpenStudy (anonymous):

Is it simplified to a * CUBEROOT(-16b^8) ? or in equation form \[a*\sqrt[3]{-16b^8}\]

OpenStudy (akshay_budhkar):

\[2ab^2\sqrt[3]{2b^2}\]

OpenStudy (anonymous):

care to explain?

OpenStudy (akshay_budhkar):

i just simplified it further by writing 16 as 2 * 8 ( cube root of 8 is 2) similarly writing b^8 as b^2 *b^6 ( cube root of b^6 is b^2)

OpenStudy (akshay_budhkar):

are u still confused?

OpenStudy (anonymous):

lemme think for a second

OpenStudy (akshay_budhkar):

sure its easy ..

OpenStudy (anonymous):

that makes me feel better...

OpenStudy (anonymous):

and then you just took the a out right?

OpenStudy (anonymous):

will you give me a practice one to see if i can get it right?

OpenStudy (akshay_budhkar):

yes i just took it out right

OpenStudy (akshay_budhkar):

ok i will give u a question

OpenStudy (akshay_budhkar):

\[\sqrt[3]{48a^6b^5}\]

OpenStudy (anonymous):

4a^2b * cuberoot(3b^2)

OpenStudy (akshay_budhkar):

your variables a and b are correct, but there seems to be a problem in your constant.. look again and think with a cool mind

OpenStudy (anonymous):

Oops i see where i messed up

OpenStudy (akshay_budhkar):

lol its good to realize your mistakes :)

OpenStudy (anonymous):

very true

OpenStudy (akshay_budhkar):

so correct yourself

OpenStudy (anonymous):

2 is the outside coefficient, and 6 is the inside coefficient

OpenStudy (akshay_budhkar):

yup correct :D you got it :)

OpenStudy (anonymous):

yay, thanks for your help

OpenStudy (akshay_budhkar):

my pleasure :D

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