Question

find x

Answer 1

find x

^
|
|
|
here it is lol

Answer 2

we just found x yesterday

Answer 3

today we should find new and exciting things

Answer 4

Equation?

Answer 5

\[(2x)^{\log_{2} }+(3x)^{\log_{3} }=0\]

Answer 6

------------------> x <-------------------------

Answer 7

exp are exp

Answer 8

your logs have no arguemtns

Answer 9

is that spose to be:

log2(2x) + log3(3x) = 0 by chance?

Answer 10

just solve it

Answer 11

just notate it ....

Answer 12

so far youve written something thats just jibberish

Answer 13

you need arguments after the logs, you have a typo

Answer 14

i know log2(2x) + log3(3x) = 0

Answer 15

you guys are funny XD

Answer 16

ok, that I can do :) maybe

log2(2)+log2(x)+log3(3)+log3(x) = 0

log2(x)+log3(x)= -2 hmmm

Answer 17

Do you mean