help on 4, 6, 8
Find the values of X and Y for which ABCD must be a parallelagram.
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OpenStudy (anonymous):
Thanks
OpenStudy (mertsj):
3x+1=6x-4
Directrix (directrix):
4. If one pair of opposite sides of a quadrilateral is both parallel and congruent, then the quadrilateral is a parallelogram. So, 3x+1 = 6x-4 and x = 5/3.
OpenStudy (mertsj):
4x-1=x+38 (if I saw the numbers right. They are very small)
OpenStudy (anonymous):
so then X and Y would be for number 4?
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OpenStudy (mertsj):
Number 8 I don't think so but I can't see it very well. only thing I can see is that one diagonal is bisected.
OpenStudy (anonymous):
ill re send it
OpenStudy (anonymous):
|dw:1327721320626:dw|Determine weather the quadratalerl is a prallelagram
Directrix (directrix):
x = 5/3. There is no y variable. See original post above.
OpenStudy (anonymous):
Oh I see and for #6 would it be 13?
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Directrix (directrix):
Agree with Mert on #8. The quad is not a parallelogram.
OpenStudy (anonymous):
what about #
OpenStudy (anonymous):
6
Directrix (directrix):
x =13 on #6 because one pair of opposite sides is both congruent and parallel.