Question

simplify i^6 times i^8

Answer 1

(i^6)(i^8)
=i^14
=-1

Answer 2

but, is i a variable or complex number?

Answer 3

if its a variable, leave it as i^14

Answer 4

\[i^{6+8}=i^{14}=i^{4n+2}=-1\]

Answer 5

where did the i go? and where did the 4n+2 come from?

Answer 6

14= 4 (3) +2 which is of the form 4n +2

Answer 7

is "i" complex number?

Answer 8

wait, ofree, answer the question

Answer 9

Is i a complex number?

Answer 10

or is it a variable?

Answer 11

\[x^a \times x^b= x^{a+b}\] Remember that.. i believe it is a variable

Answer 12

so your answer is \[i^{14}\]

Answer 13

What Akshay is doing is showing you how to figure out the system of complex numbers.
the root of -1 is called i. Therefore, i^2=-1 and i^4 is 1. 4n+2 refers to this pattern for complex numbers.

Answer 14

the only options are i, -1, -i, 1 so i^14 is not the answer