Question

the sum of the two smallest of five consecutive odd integers is 50 less than the sum of the other three integers. What is the smallest integer?

Answer 1

The five integers are:
x
x+2
x+4
x+6
x+8

Answer 2

The sum of the two smallest is x + x+2 or 2x+2

Answer 3

That sum, 2x+2 is 50 less than the sum of the other three.
The sum of the other three is 3x+18
So we have
2x+2=3x+18-50

Answer 4

Can you solve that?

Answer 5

ya give me a min and I'll tell you the answer

Answer 6

x=-34

Answer 7

I got 34 but that is not an odd integer.

Answer 8

Are you sure the problem said odd?

Answer 9

my mistake it says even

Answer 10

Did you find you mistake in getting -34?

Answer 11

3x+18-50=2x+2

Answer 12

3x+34=2x

Answer 13

34=-1x

Answer 14

x=-34

Answer 15

3x+18-50=2x+2
3x-32 = 2x=2
3x=2x+34
x=34

Answer 16

you didn't move the two from the other side cuz 18-50 is -32 then plus 2 is -30

Answer 17

wait I see what you did