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Solve: x^3-2x^2-5x+6=0
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first thing I do in these situations is check if you get lucky and have +/-1 be a solution...
Answer: x= -2 , x= 1 and x = 3
Did you try synthetic division?
No, I haven't tried synthetic division because I was unsure how to start it? Do I just pick number I think will work?
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The factors of the constant term, which is 6, are +-1, +-2, +-3, +-6. Would you agree?
The coefficient of the x^3 term is 1. So the possible rational roots are the factors of the constant term divided by the factors of 1.
Yes that makes sense. Okay, so now I try all of those numbers?
\[\pm1, \pm2,\pm3, \pm 6\]
i usually start with the small ones.
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