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Write the equation of the parabola that is congruent to y=x^2: a) has a minimum at (-3,0) b) has a maximum at (0,7) c) has a minimum at (5,6)
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a ) y = x -3 b) y = x + 7 c) y = (x -5) + 6
how did yu do it
ok so you take the maximum/ minimum of your equation and that will be your value for y = (x -h) + k k is your vertical translation and h is your horizantal translation
wudn't it be y=(x+3)+k
oh my bad yeah the first one is y = (x -3) dont include the values if there are not given
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no its a pos 3 not a neg 3
rem yu need to do it opp sign
my bad again y = (x+ 3)
LOL ok :D
ty
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