Question

How do I find the zeroes for this problem?

(x+5)^2/(x-3)^2+(x+5)^3/(x-3)^3 = 0

Answer 1

x=-5 I believe you are solving just the numerators

Answer 2

you have to combine the fractions and make it one.
then find the x values that will make the numerator part 0.

Answer 3

-1 too, I think

Answer 4

I did a quick graph and it shows -5 as a zero and -1

Answer 5

(x+5)^2/(x-3)^2+(x+5)^3/(x-3)^3 = 0
[ (x+5)^2(x-3) + (x+5)^3 ] /(x-3)^3 = 0
Factor the numerator to get (x+5)^2(2x+2)=0
=>
x=-5 (multiplicity 2) and x=-1 as precal got.

Answer 6

Thanks! I was so very close...