Question

A wire carries a current of 1ampere .How many electrons pass a point in the wire an each second?

Answer 1

1c of charges flow in one second..
and charge on each electron is 1.6 multiplied by 10 raised to -16 c

so now can you tell .. how many electrons?

Answer 2

-19 i mean sorry!

Answer 3

simple,

I=q/t

q=no of electrons*charge on an electron.
q=no of electrons*(1.6*10^-19)

use above equation,
\[I=(n*1.6*10^{-19})/t\]

separate "n"

\[n=(I*t)/(1.6*10^{-19})\]

substitute values,
\[n=(1*1)/(1.6*10^{-19})\]
n=\[6.25*10^{18} electrons\]