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A wire carries a current of 1ampere .How many electrons pass a point in the wire an each second?
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1c of charges flow in one second.. and charge on each electron is 1.6 multiplied by 10 raised to -16 c so now can you tell .. how many electrons?
-19 i mean sorry!
simple, I=q/t q=no of electrons*charge on an electron. q=no of electrons*(1.6*10^-19) use above equation, \[I=(n*1.6*10^{-19})/t\] separate "n" \[n=(I*t)/(1.6*10^{-19})\] substitute values, \[n=(1*1)/(1.6*10^{-19})\] n=\[6.25*10^{18} electrons\]
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