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Mathematics 20 Online
OpenStudy (anonymous):

prove sigma n^2=n(n+1)(2n+1)/6

OpenStudy (anonymous):

i know!

OpenStudy (anonymous):

that is \[\sum_{1}^{n}\]n^2

OpenStudy (anonymous):

then tell?

OpenStudy (anonymous):

NCERT

OpenStudy (anonymous):

For reference, you should not use the same variable for the upper limit as you do in the expression. Instead, say \[ \sum_{k=1}^n\space k^2 \]

OpenStudy (anonymous):

Do you mean prove it or derive it? It can be proved with induction.

OpenStudy (anonymous):

sorry i meant derive it?

OpenStudy (anonymous):

http://www.trans4mind.com/personal_development/mathematics/series/sumNaturalSquares.htm In the first proof I don't get this part "...Because \(Δ_3\) is a constant, the sum is a cubic of the form..."

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