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prove sigma n^2=n(n+1)(2n+1)/6
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i know!
that is \[\sum_{1}^{n}\]n^2
then tell?
NCERT
For reference, you should not use the same variable for the upper limit as you do in the expression. Instead, say \[ \sum_{k=1}^n\space k^2 \]
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Do you mean prove it or derive it? It can be proved with induction.
sorry i meant derive it?
http://www.trans4mind.com/personal_development/mathematics/series/sumNaturalSquares.htm In the first proof I don't get this part "...Because \(Δ_3\) is a constant, the sum is a cubic of the form..."
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