Question

What is the equation of the line perpendicular to x+5y=-2 passing through (-3,-4) in standard form?

Answer 1

slope*(-1/5)=-1
slope=5
y+4=5(x+3)
y=5x+11

Answer 2

find the gradient of your line.... then the gradient of the perpendicular is -1/m

then use point gradient to find the equation..

Answer 3

that is in slope-intercept how do I put y=5x+11 in standard ?

Answer 4

5x-y=-11

Answer 5

so everything on the left hand side.... y - 5x -11 = 0

Answer 6

moving the 11 to the left hand side would make it positive right?

Answer 7

i think I will go with 5x-y=-11, thanks.

Answer 8

yup thats it
my pleasure XD