Question

7. Evaluate 1/2a^–4b^2 for a = –2 and b = 4.
A. 2
B. 1/2
C. 3
D. 4

Answer 1

Is it \( \huge \frac 12a^{–4}b^2 \)

Answer 2

Yes

Answer 3

Then the answer is B. 1/2.

Answer 4

Convert everything to power of \( 2 \) and then use laws of indices.

Answer 5

we have \[1/2 a^{-4} b^2\]
substitute a=-2 and b=4
we get
\[1/2 (-2)^{-4} (4)^2\]
or \[\frac{16}{2*16}\]
cancelling the 16 from numerator and denominator
\[\frac{1}{2}\]