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Mathematics 16 Online
OpenStudy (anonymous):

ABE+ACE+ADE=2012 What number represents which letter?

OpenStudy (anonymous):

E = 4

OpenStudy (vishal_kothari):

it has infinitely many solution....

OpenStudy (anonymous):

But every cryptogram has a unique solution right?

OpenStudy (anonymous):

no it's certainly don't have infinitely solutions

OpenStudy (vishal_kothari):

the set of numbers are not given ....

OpenStudy (anonymous):

and letters can represent only 1 digit

OpenStudy (vishal_kothari):

so sorry..i got it...i thought we considered each as a single variable....

OpenStudy (anonymous):

A=6 E=4 B+C+D=20 so you can choose any numbers e.g. B=2 C=9 D=9

OpenStudy (radar):

or b=7, c=5, d=8

OpenStudy (anonymous):

Thank you everyone :)

OpenStudy (anonymous):

i am willing to bet you are making the assumption (though not stated) that different letters represent different numbers, so i would go with radar's answer

OpenStudy (anonymous):

Unfortunately not, I'll take the A + B + C + D + E and then the answer is the number I need. :)

OpenStudy (phi):

assuming each letter represents a distinct digit, there are two triplets that satisfy the condition 634,684,694 and 654,674,684

OpenStudy (anonymous):

so you should have stated at the beginning that you need to find A+B+C+D+E

OpenStudy (anonymous):

No, why should I? Once I got help with the letters, it was not so hard to plus them together.

OpenStudy (anonymous):

because it would be easier to solve it

OpenStudy (anonymous):

No, it would not make any difference.

OpenStudy (anonymous):

well i have solved it, so i can say that it would be easier :P

OpenStudy (anonymous):

also there might be such problems that you can't get answers to all parts only sum of them so better post full question

OpenStudy (phi):

@97 I agree with Tomas, it is much easier to find the sum of A,B,C,D,E than to find all permutations. Why don't you try for yourself and see.

OpenStudy (anonymous):

But I needed two responses, and the last one I could actually figure out myself.

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