find the limit of (x+7)/(x^2 -6x + 9) as x approaches 3. please show all calc involved
is 3 a bad value for x?
what do you mean?
what makes a bad fraction?
when i plug in 3, i get 10/0...thats not good according to my teacheelser but dont know what else to do
right, /0 is a bad fraction so x=3 makes this go bad
can we undo the offending part with algebra?\[\frac{(x+7)}{(x-3)^2}\] prolly not
lol i love your definition of the term bad fraction i like to say discontinuous at such and such but bad fraction is a good term
http://www.wolframalpha.com/input/?i=limit%7Bx+to+3%7D+%28x%2B7%29%2F%28x-3%29%5E2
So anyways since there is no way to force this fraction to be continuous at x=3 then the limit does not exist
inf aint a good answer then is it :)
it aint a real number so ....
does not exist is fine but saying it approaches infinity gives a little more info on that "does not exist" phrase
Infinty and does exists are not same right?
exist means a definitive value; infinity is more a direction than a value i believe
right amistre
This limit exists and it is infinity...
what about x^2-x-20/2x^2-32, as x approaches -4
happy birthday myininaya
infinity is not a number
Right hand limit =left hand limit = infinity
so it does not exist
I know but infinity is not same as undefined.
infinity is fine to say when both sides are approaching infinity (same for negative infinity) but i feel it is also okay to say it dne since infinity is not a number
amistre whats the screenshot for
but can anyone help with the last question i posted please
hes just saying the question in the window thingy is not the same as the question you asked
For this question I would say that the limit is infinity, but if for the purposes of some questions where only finite limits are applicable then an infinite limit might be considered DNE.
I'd probably say infinity too, but with the understanding that the limit really does not exist...infinity is just the direction that the function is going.
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