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f(x) = x-x^3 a = -0.2 slope =??
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could you clarify the question? what does a refer to?
tangents
Let f(x) = x-x^3. determine the approximate slope of the line tangent of f at (a, f (a)).
a = -0.2 slope=?
I think derivitives
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ok thank you the slope of f(x) can be determined by taking derivative f'(x) =1 - 3x^2 now plug in x = -0.2 f'(-0.2) = 1 - 3(-.2)^2 = 0.88
so 0.88 would be the slope?
yes f'(x) is same thing as slope at point (x, f(x))
thank you
do you know how to take the derivative of polynomials?
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d/dx x^n = n*x^(n-1)
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