Question

A pawn broker buys a TV set and a computer for $600. He sells the Computer at a markup of 30% and the TV at a markup of 20%. If he makes a profit of $165 on the sale of two items, what did he pay for the computer?

Answer 1

if he pays say "x" dollars for the computer then since the total is $600 he must pay 600 - x dollars for the tv. his profit on the computer is
\[.3x\] and his profit on the tv is
\[.2(600-x)\] and you know this totals 165 so set
\[.3x+.2(600-x)=165\] and solve for x

Answer 2

probably easiest to start with
\[3x+2(600-x)=1650\] so you don't have the messy demicals

Answer 3

ok perfect thank you I was close when I set my equation up but I think I caught where I was messing up