Solve the system of equations using the elimination method.
3x-4y=0
2x-3y=-1

Question

Solve the system of equations using the elimination method.
3x-4y=0
2x-3y=-1

anonymous · Answer

how do i solve this?

anonymous · Answer

multiply the first equation by 2 and the 2nd equation by -3 and add them together

anonymous · Answer

2(3x-4y=0) => 6x-8y=0
-3(2x-3y=-1)=>-6x+9y=3

adding them together give you y=3

anonymous · Answer

6x-8y=0-eqn1
6x-9y=-3-eqn2
eqn1-eqn2=>y=3
6x-24=0
6x=24
x=4

anonymous · Answer

okay. got iy.

campbell_st · Answer

Label the equations   3x - 4y = 0    (1) and 2x - 3y = -1  (2)

the 2 x (1) - 3 x (2)
 this will eliminate x as shown below

    6x - 8y = 0
  -6x+ 9y = -3

y = -3    hence y = -3   and sub into either equation to find x,  x = 4

campbell_st · Answer

oops y = 3

anonymous · Answer

okay. thanks you guys! i really appreciate it! :)