Question

Solve the system of equations using the elimination method.
3x-4y=0
2x-3y=-1

Answer 1

how do i solve this?

Answer 2

multiply the first equation by 2 and the 2nd equation by -3 and add them together

Answer 3

2(3x-4y=0) => 6x-8y=0
-3(2x-3y=-1)=>-6x+9y=3

adding them together give you y=3

Answer 4

6x-8y=0-eqn1
6x-9y=-3-eqn2
eqn1-eqn2=>y=3
6x-24=0
6x=24
x=4

Answer 5

okay. got iy.

Answer 6

Label the equations 3x - 4y = 0 (1) and 2x - 3y = -1 (2)

the 2 x (1) - 3 x (2)
this will eliminate x as shown below

6x - 8y = 0
-6x+ 9y = -3

y = -3 hence y = -3 and sub into either equation to find x, x = 4

Answer 7

oops y = 3

Answer 8

okay. thanks you guys! i really appreciate it! :)